Solve the initial value problem below using the method of Laplace transforms. y" - 36y=216t-12 e 6t, y(0) = 0, y'(0) = 3

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Solve The Initial Value Problem Below Using The Method Of Laplace Transforms Y 36y 216t 12 E 6t Y 0 0 Y 0 3 1 (15.07 KiB) Viewed 35 times

Solve The Initial Value Problem Below Using The Method Of Laplace Transforms Y 36y 216t 12 E 6t Y 0 0 Y 0 3 2 (19.44 KiB) Viewed 35 times

Solve The Initial Value Problem Below Using The Method Of Laplace Transforms Y 36y 216t 12 E 6t Y 0 0 Y 0 3 3 (9.08 KiB) Viewed 35 times

Solve the initial value problem below using the method of Laplace transforms. y" - 36y=216t-12 e 6t, y(0) = 0, y'(0) = 31 Click here to view the table of Laplace transforms. Click here to view the table of properties of Laplace transforms. y(t) = (Type an exact answer in terms of e.) ***

Use the Laplace transform table and the linearity of the Laplace transform to determine the following transform. Complete parts a and b below. (21²e-t-et cos √6t} Click the icon to view the Laplace transform table. a. Determine the formula for the Laplace transform. (21²-61-ecos √6t) = b. What is the restriction on s? s>(Type an integer or a fraction.) со (Type an expression using s as the variable.)

Determine¹(F). - 2s²-22s-42 (s+ 3)² (s+6) F(s)=- Click here to view the table of Laplace transforms. Click here to view the table of properties of Laplace transforms.