A) The second directional derivative of f(x, y) is Du2f(x, y) = Du[Duf(x, y)]. If f(x, y) = x³ + 5x²y + y³ and u = D2f(2

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answerhappygod
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A) The second directional derivative of f(x, y) is Du2f(x, y) = Du[Duf(x, y)]. If f(x, y) = x³ + 5x²y + y³ and u = D2f(2

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A The Second Directional Derivative Of F X Y Is Du2f X Y Du Duf X Y If F X Y X 5x Y Y And U D2f 2 1
A The Second Directional Derivative Of F X Y Is Du2f X Y Du Duf X Y If F X Y X 5x Y Y And U D2f 2 1 (53.35 KiB) Viewed 20 times
A) The second directional derivative of f(x, y) is Du2f(x, y) = Du[Duf(x, y)]. If f(x, y) = x³ + 5x²y + y³ and u = D2f(2, 3) = B) Use the Chain Rule to find dw/dt. dw dt dw dt C) Use the Chain Rule to find dw/dt. = = dz dt W = = In (√x² + y² + z²), w = xey/z₁ x = t³, y = 1-t, 13' 13 12 sin cost+81 tant sect 16 sin + 4 cost + 81 tanr D) Use the Chain Rule to find dz/dt. calculate Du²f(2, 3). -2²), x = 4 sin(t), y = 2 cos(t), z = 9 tan(t) z = sin(x) cos(y), x = √t, y = 5/t 3 2 -5(cos()) 5( cos()) 61 - - ) z = 6 +7t
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