QUESTION 6 Solve the IVP using Taylor's series( 3rd deg polynomial). dy/dx = 3x2y; y(1)=1 y'(1) = y"(1)= y" (1)= y(1.4)=

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QUESTION 6 Solve the IVP using Taylor's series( 3rd deg polynomial). dy/dx = 3x2y; y(1)=1 y'(1) = y"(1)= y" (1)= y(1.4)=

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Question 6 Solve The Ivp Using Taylor S Series 3rd Deg Polynomial Dy Dx 3x2y Y 1 1 Y 1 Y 1 Y 1 Y 1 4 1
Question 6 Solve The Ivp Using Taylor S Series 3rd Deg Polynomial Dy Dx 3x2y Y 1 1 Y 1 Y 1 Y 1 Y 1 4 1 (67.6 KiB) Viewed 15 times
QUESTION 6 Solve the IVP using Taylor's series( 3rd deg polynomial). dy/dx = 3x2y; y(1)=1 y'(1) = y"(1)= y" (1)= y(1.4)= True value at x=1.4 (2 decimal places) (2 decimal places)
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