solutions of sample problem no. 1 and Calculate the A/C capacity we've got from our sample problem. mo 3 35°C & 26°C DB Outside air WB ms MR A/C Air Conditioner Capacity=ms (h4 -h₁) I ms 25°C. DB & 50%RH Condition Space Qs = 40,428.78935W QL = 26,554.55W
35 °C strid 26 "Cwa { GROUND FLOOR: Poyahrometrie Calculation A/C. Ch-254233.0001 W OL- 227112. 1723 W R0.777 Than, XHT - & Outdoor Condition: 38- Cinnune 2° Cwn hwe - Cpt W.(hgo) H-80.777 KJ/KA W.. 0 0170 kg/kg 1.0002 (35) } W.-0.01775041/ hilofkan W. - XXAXXX.0401 W 16167 KAKIE W(2565.4) VA RAVY P 101326 T'H 1(1 P -2.012733279 KI'M 101.325 25°Cuu& SUX RH 0.5073516177 07X7 (t + 272) C.-234233.0901 W QT- 461675 2624 w 1778411x7 bw/Ran 2.012733279 Kla
For retum air condition. 3 PAC, 50%%% RH 0.622 1 P Vn Wn Than. hk- Cpt + Waha on G hn 101.32S Ventilation Load: Vo - 16- - 50.3415997 k/kg: mn 0.207 (25 1 273) (O.8 0.0973095731 13 - 1X01.265175 9.007567112 X40 1.0062 (256) + 0.007567112 s. 10-* kRwV/KR. (2547.3 k/kr) 0.622 (05 3.171kPa) 101.325- m.. 3.171KPA) ma 1.801365175 24 THES 0.8574937713 kr. 24 (. 234.2330501- (0.5 x 171KPE kpt Imª 1000 L -0.0574937713 m.GRAT 5.350945816 kg 4.001365175 m₂ (1.0062)(35.25) KH 4 23.27097934 MK -MI 23.27897934 KR. - 5.350045016 M 17.92813352 kg KR KR 5
(5.350845816) (0.0177594137 kxww/kx...) m..w..+mWW + (17.9701352) (9.887567112 x 10 kgwv/kda) - 23.270979:14(w..) mhm..h... (5.35045816) (nn.777 kJ/kx) + (17.9281352 "S) (50.3415997 k/kr) 21.270197934 (1) For bl. w -0.01169696935 kr/kg From Paychrometric Chart: SHF- moto + mar (S.350045816) (35^C) + (17.921:13 1352 *) (25-) - 21.27897934 (r.) 27.2905740G C It-57.33740107 kl/kg SHC t hy - hy mete TL 18.6°C 1.0062 (25-18.6) 50:1415997- h.. b₁37.64893978 kJ/kg A/C: Capacity 458.3273022 kW x -0.5073546477 A/C Capariry me (he h₁.) A/C Capacity - 25.27897934* (S7.33740187 kl/kx-37.61893978 kJ/kx) ITUR X16 KW <-130,3547503 TOR
Refer the psychrometric Refer the psychrometric solutions of sample problem no. 1 and Calculate the A/C capacity we've got from our sample probl
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