A student determines that an aqueous solution that contains 0.149 M potassium hypochlorite and 7.50×10-2 M hypochlorous

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A student determines that an aqueous solution that contains 0.149 M potassium hypochlorite and 7.50×10-2 M hypochlorous

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A Student Determines That An Aqueous Solution That Contains 0 149 M Potassium Hypochlorite And 7 50 10 2 M Hypochlorous 1
A Student Determines That An Aqueous Solution That Contains 0 149 M Potassium Hypochlorite And 7 50 10 2 M Hypochlorous 1 (253.68 KiB) Viewed 24 times
A Student Determines That An Aqueous Solution That Contains 0 149 M Potassium Hypochlorite And 7 50 10 2 M Hypochlorous 2
A Student Determines That An Aqueous Solution That Contains 0 149 M Potassium Hypochlorite And 7 50 10 2 M Hypochlorous 2 (171.82 KiB) Viewed 24 times
A Student Determines That An Aqueous Solution That Contains 0 149 M Potassium Hypochlorite And 7 50 10 2 M Hypochlorous 3
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A Student Determines That An Aqueous Solution That Contains 0 149 M Potassium Hypochlorite And 7 50 10 2 M Hypochlorous 4
A Student Determines That An Aqueous Solution That Contains 0 149 M Potassium Hypochlorite And 7 50 10 2 M Hypochlorous 4 (327.9 KiB) Viewed 24 times
A student determines that an aqueous solution that contains 0.149 M potassium hypochlorite and 7.50×10-2 M hypochlorous acid, also has an H3O+ concentration of 2.27x10-8 M. Based on these data, calculate the value of the equilibrium constant K for the equilibrium: HCIO(aq) + H₂0 H30+ (aq) + CIO (aq) Calculate K as is usually done, omitting the solvent, water, from the expression for K: K = Submit Answer Retry Entire Group 9 more group attempts remaining
A student determines that an aqueous solution that contains 0.262 M sodium formate and 0.238 M formic acid, also has an H3O+ concentration of 1.98x10-4 M. Based on these data, calculate the value of the equilibrium constant K for the equilibrium: HCOOH(aq) + H2O=H3O+(aq) + HCOO-(aq) Calculate K as is usually done, omitting the solvent, water, from the expression for K: K=
Dinitrogen tetraoxide is a colorless gas that dissociates into nitrogen dioxide, a reddish brown gas. N₂O4 (g) 2 NO₂ (g) An experiment was run to demonstrate that this is a dynamic equilibrium. Starting with a special form of N₂04 where one of the oxygens was isotopically labeled (180 instead of 160), the system was then allowed to reach equilibrium. 18 N-N If the equilibrium is NOT dynamic the forward reaction would simply run until equilibrium is reached and then cease. Under this condition which of the structures below would be observed for N₂O4? If the equilibrium IS dynamic the forward and reverse reactions run even after equilibrium is reached. Under this condition which of the structures below would be observed for N₂04 ? 10
of the equilibrium is NOT dynamic the forward reaction would simply run until equilibrium is reached and then cease. Under this condition which of the structures below would be observed for N₂O4 ? If the equilibrium IS dynamic the forward and reverse reactions run even after equilibrium is reached. Under this condition which of the structures below would be observed for N₂O4 ? Put letters in alphabetical order. If none are correct enter NONE. Do not put spaces or commas or other characters between your answers. A. B. 18 O 18 N-N 18, N-N 18 Submit Answer C. D. N-N 18 BO 180 N-N 18 80 D Retry Entire Group 9 more group attempts remaining
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