Consider the following system at equilibrium where AH = 10.4 kJ, and Ke = 2HI(g) H₂(g) + 12 (9) When 0.21 moles of H₂(g)
Posted: Sun Jul 10, 2022 4:07 pm
Consider the following system at equilibrium where AH = 10.4 kJ, and Ke = 2HI(g) H₂(g) + 12 (9) When 0.21 moles of H₂(g) are removed from the equilibrium system at constant temperature: The value of Ke O increases decreases O remains the same The value of Qe O is greater than Ke O is equal to Ke O is less than Ke The reaction must O run in the forward direction to reestablish equilibrium O run in the reverse direction to reestablish equilibrium O remain in the current position, since it is already at equilibrium The concentration of H₂ will O increase decrease O remain the same 0.0180, at 698 K: