Consider the following system at equilibrium where AH = 10.4 kJ, and Ke = 2HI(g) H₂(g) + 12 (9) When 0.21 moles of H₂(g)

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answerhappygod
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Consider the following system at equilibrium where AH = 10.4 kJ, and Ke = 2HI(g) H₂(g) + 12 (9) When 0.21 moles of H₂(g)

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Consider The Following System At Equilibrium Where Ah 10 4 Kj And Ke 2hi G H G 12 9 When 0 21 Moles Of H G 1
Consider The Following System At Equilibrium Where Ah 10 4 Kj And Ke 2hi G H G 12 9 When 0 21 Moles Of H G 1 (33.05 KiB) Viewed 24 times
Consider the following system at equilibrium where AH = 10.4 kJ, and Ke = 2HI(g) H₂(g) + 12 (9) When 0.21 moles of H₂(g) are removed from the equilibrium system at constant temperature: The value of Ke O increases decreases O remains the same The value of Qe O is greater than Ke O is equal to Ke O is less than Ke The reaction must O run in the forward direction to reestablish equilibrium O run in the reverse direction to reestablish equilibrium O remain in the current position, since it is already at equilibrium The concentration of H₂ will O increase decrease O remain the same 0.0180, at 698 K:
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