1294 grams of ice at -73.6 degrees Celsius is mixed with 362 grams of steam at 141 degrees Celsius. Assuming that at equ

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answerhappygod
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1294 grams of ice at -73.6 degrees Celsius is mixed with 362 grams of steam at 141 degrees Celsius. Assuming that at equ

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1294 grams of ice at -73.6 degrees Celsius is mixed with362 grams of steam at 141 degrees Celsius. Assuming that atequilibrium the only phase remaining will be water, what will thefinal temperature of the water be? Specific heats: steam = 1.86J/gC; water = 4.18 J/gC; ice = 2.09 J/gC; =2259.1 J/g; =333.8 J/g
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