A basketball is pressurized to a gauge pressure of PG = 65 kPa when at the surface of a swimming pool. (Patm = 101 kPa).

[answerhappygod]

A basketball is pressurized to a gauge pressure of PG = 65 kPawhen at the surface of a swimming pool. (Patm = 101 kPa). The ballis then submerged in the pool of water which has a density ρ = 1000kg/m3. Assume the ball does not change in mass, temperature, orvolume as it is submerged.
1.Write an equation for the pressure differenceΔP between the inside and outside of the ball when itis submerged a distance y below the surface ofthe water.
2. Solve the pressure equation for the depth (in meters) atwhich the pressure difference between the inside and outside of theball will become zero. At this depth the pressure inside thebasketball is the same as the pressure outside the ball.
3. At what depth, in meters, would the pressure differencebetween the inside and outside of the ball be zero if the ball weresubmerged in mercury (ρ = 13,500 kg/m3) instead of inwater?