A thin rod has uniform charge per tength z. The distance between point A and point 8 is SW and the distance between poin

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A thin rod has uniform charge per tength z. The distance between point A and point 8 is SW and the distance between poin

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A Thin Rod Has Uniform Charge Per Tength Z The Distance Between Point A And Point 8 Is Sw And The Distance Between Poin 1
A Thin Rod Has Uniform Charge Per Tength Z The Distance Between Point A And Point 8 Is Sw And The Distance Between Poin 1 (31.58 KiB) Viewed 39 times
A Thin Rod Has Uniform Charge Per Tength Z The Distance Between Point A And Point 8 Is Sw And The Distance Between Poin 2
A Thin Rod Has Uniform Charge Per Tength Z The Distance Between Point A And Point 8 Is Sw And The Distance Between Poin 2 (40.94 KiB) Viewed 39 times
A Thin Rod Has Uniform Charge Per Tength Z The Distance Between Point A And Point 8 Is Sw And The Distance Between Poin 3
A Thin Rod Has Uniform Charge Per Tength Z The Distance Between Point A And Point 8 Is Sw And The Distance Between Poin 3 (36.67 KiB) Viewed 39 times
A thin rod has uniform charge per tength z. The distance between point A and point 8 is SW and the distance between point A and point C is BW and the distance between point C and point P is 2W. We introduce an integration variable h with h-0 chosen to be at point B and the h direction to the left. The small red segment has length dh and charge do. We want to find the electric field at point P Drow it out-label the oll the lengths and the integration variable! L.. >+x B P What is the charge in the small segment da? (Select
>+x i. What the charge in the small segment dq? A dE B Kdg (3W+h) C ii. What is x component of the electric field due da-dh (A thru F) below. [Select] da z dh/(8H) dqz dh/(5H) M P [Select) Select da 5H/dh da z/dh V gment? Choose from choices
il. What is x component of the electric field due to the charge do in the small segment? Choose from choices (A thru F) below. (Select] A dE B. dE C. dE,- D. dE,= E. dE,- F. dE Kile (3W-+-A) ((SW+A)* +4W)/ Kdq (3W+A) Kdg h (SW4A)/ Kde h (N³+4W*)M/² Kdg (3W+X)³ +4W2 Kdg 9W iii. What are the limits of integration? [Select] Select 3W<h<8W 0<h<8W 5W<h<8W 0<h<3W 0<h <5W Next-
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