15.0 mg of a sparingly soluble salt (X3Y2(s)) with a solubility product constant of 1.50 x 10−21 is placed into 100 cm

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answerhappygod
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15.0 mg of a sparingly soluble salt (X3Y2(s)) with a solubility product constant of 1.50 x 10−21 is placed into 100 cm

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15.0 mg of a sparingly soluble salt (X3Y2(s)) with a solubility product constant of 1.50 x 10−21 is placed into 100 cm3 of water. If the salt produces X2+(aq) and Y3−(aq) ions, then its molar solubility is:
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