Note: Always use the unrounded off value in solving forthe unknowns. Use 2 decimal places to round off your finalanswers and it must be in engineering notation. Use26.00m as the constant to determine re'. All currents mustbe assumed in the correct direction (always positive), voltagemeasurements will always be with respect to ground and gain dependson the amplifier configuration. So be mindful of the sign forvoltage and gain.
C₂ www www re = [re] Zi = [Zi] Av = [Av] R₁ R₂ RIN(BASE) = [RINBASE] IB = [IB] -Vcc Rc RE C3 Zi Vo Given : B = 100, VCC = -10, RB1 = 32k, RB2 = 5k, RC = 5k, RE = 500 Solve for RIN(BASE), IB, re, Zi, Av V₁
Compute for VTH and RTH First, compute for RB2 (EQ). It is the parallel combination of RB2 and RIN(BASE). RIN(BASE) = (B + 1). RE RB2 (EQ) = 1/(1/RB2 + 1/RIN(BASE)) VTH = VCC. (RB2(EQ) / (RB1+RB2(EQ)) RTH = 1/(1/RB1 + 1/RB2(EQ)) IB = (VTH-VBE) / (RTH+ ((B+1). RE)) IC = B.IB IE = IB + IC
To compute for Zi, Zo and Av, Input impedance is just the parallel combination of RE and re. Zi = RE || re Zo = RC Vo = a.le.RC; Vi = le-re; Av = Vo / Vi; Av = (a-le-RC) / (le-re) Av = (a-RC) / re
Note: Always use the unrounded off value in solving for the unknowns. Use 2 decimal places to round off your final answ
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