Write a program in RISC-V assembly to convert an ASCII string containing a positive or negative integer decimal string t

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Write a program in RISC-V assembly to convert an ASCII stringcontaining a positive or negative integer decimal string to aninteger. Your program should expect register x10 to hold theaddress of a null-terminated string containing an optional "+" or"−" followed by some combination of the digits 0 through 9. Yourprogram should compute the integer value equivalent to this stringof digits, then place the number in register x10. If a non-digitcharacter appears anywhere in the string, your program should stopwith the value −1 in register x10. For example, if register x10points to a sequence of three bytes 50, 52, 0, which represent thenull-terminated string "24\0", then once the program stops,register x10 should contain the integer value of 24 (or 0x18 inhex). Hints: The RISC-V mul instruction takes two registers as input. There isno "muli" instruction. Thus, just store the constant 10 in aregister.For testing purposes: you can add this at the bottom of yourassembly file:.data mystr: .byte 50, 52, 0
DO NOT SEND ME THIS PLEASE :# you can use string as well ...

Write A Program In Risc V Assembly To Convert An Ascii String Containing A Positive Or Negative Integer Decimal String T 1 (324.66 KiB) Viewed 79 times

Program: #str2int.s .data str: .text la x10, str jal x0, str2int jalr str2int: asciiz "-24" 1b x5, (x10) addi x8, x0,45 beq x5, x8, negint addi x8, x0,43 beq x5, x8, posint. jal x0, convert negint: li x19,1 addi x10, x10,1 jal, x0, convert posint: li x19,0 addi x10, x10,1 convert: addi x18,x0,10 add x9,x0, x0 L1: 1b x5,0 (x10) beq x5, x0, exitloop addi x8, x0,48 blt x5, x8, fail addi x8, x0,58 bge x5, x8, fail addi x5,x5,-48 mul x9,x9,x18 add x9,x9,x5 addi x10, x10,1 jal x0, L1 fail: addi x10, x0,-1 jal x0, return exitloop: beq x19, x0, posret neg x9,x9 posret: mv x10,x9 return: jalr x0,0 (x1) #load address of null terminated string into x10 # call function str2int #End of the program #load first byte of the null terminated string #load ascii value of into x8 goto label negint # if first character is #load ascii value of + into x8 #if first character is '+ goto label posint # if first character is neither - nor'+', goto label convert # if first character is -, set flag x19 to 1 #goto address of next byte #goto label convert # if first character is '+', set flag x19 to 0. #goto address of next byte #set x18-10 #set sum (x9) to 0 #load a byte from string # if the current byte is null character, goto exitloop #x8-ascii of '0' # if current character is non-digit character, goto label fail # x8-ascii of ':', (':' is the next character after '9' in ascii chart) #if current character is non-digit character, goto label fail #convert character digit to integer digit #multiply the current result (x9) by 10 # add the current digit to x9 #move to next byte. #repeat the loop L1 #save -1 in x10, if non-digit character appears #goto label return # if x19 is -1, take negation of the sum #copy the integer into x10 #return to caller.