(c) Suppose n = 49 and p = 0.25. (For each answer, enter a number. Use 2 decimal places.) n-p= 12.25 n-q = 36.75 Can we

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(c) Suppose n = 49 and p = 0.25. (For each answer, enter a number. Use 2 decimal places.) n-p= 12.25 n-q = 36.75 Can we

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C Suppose N 49 And P 0 25 For Each Answer Enter A Number Use 2 Decimal Places N P 12 25 N Q 36 75 Can We 1
C Suppose N 49 And P 0 25 For Each Answer Enter A Number Use 2 Decimal Places N P 12 25 N Q 36 75 Can We 1 (24.37 KiB) Viewed 73 times
(c) Suppose n = 49 and p = 0.25. (For each answer, enter a number. Use 2 decimal places.) n-p= 12.25 n-q = 36.75 Can we approximate p by a normal distribution? Why? (Fill in the blank. There are four answer blanks. A blank is represented by be approximated by a normal random variable because .p. first blank Yes O No second blank can cannot third blank On-q exceeds On-p exceeds both n-p and n-q exceed n-p and n-q do not exceed On-q does not exceed On-p does not exceed fourth blank (Enter an exact number.) What are the values of , and a? (For each answer, enter a number. Use 3 decimal places.)
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