According to a recent study, 12% of peanut M&M's are brown, 18% are yellow, 18% are red, 27% are blue, 9% are orange, an

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According To A Recent Study 12 Of Peanut M M S Are Brown 18 Are Yellow 18 Are Red 27 Are Blue 9 Are Orange An 1 (66.51 KiB) Viewed 102 times

According to a recent study, 12% of peanut M&M's are brown, 18% are yellow, 18% are red, 27% are blue, 9% are orange, and 15% are green. Assume these proportions are correct and suppose you randomly select four peanut M&M's from an extra-large bag of the candies. Calculate the following probablities. Also calculate the mean and standard deviation of the distribution. Round all solutions to four decimal places, if necessary. Compute the probability that exactly two of the four M&M's are orange. P(z = 2) = Compute the probability that two or three of the four M&M's are orange. P(x = 2 or z = 3) = Compute the probability that at most two of the four M&M's are orange. P(x ≤ 2): = Compute the probability that at least two of the four M&M's are orange. P(x ≥ 2) If you repeatedly select random samples of four peanut M&M's, on average how many do you expect to be orange? HI orange M&M's With what standard deviation? σ= orange M&M's k