If A Ball Is Thrown Vertically Upward With An Initial Velocity Of 160 Ft S Then Its Height After T Seconds Is S 160t 1 (26.51 KiB) Viewed 60 times
If a ball is thrown vertically upward with an initial velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t². (Consider up to be the positive direction.) (a) What is the maximum height (in ft) reached by the ball? ft (b) What is the velocity (in ft/s) of the ball when it is 384 ft above the ground on its way up? ft/s What is the velocity (in ft/s) of the ball when it is 384 ft above the ground on its way down? ft/s
The height (in meters) of a projectile shot vertically upward from a point 3 m above ground level with an initial velocity of 23.5 m/s is h = 3 + 23.5t - 4.9t² after t seconds. (a) Find the velocity (in m/s) after seconds and after 4 seconds. v(2) = m/s v(4) = m/s (b) When does the projectile reach its maximum height? (Round your answer to two decimal places.) (c) What is the maximum height? (Round your answer to two decimal places.) m (d) When does it hit the ground? (Round your answer to two decimal places.) S (e) with what velocity (in m/s) does it hit the ground? (Round your answer to two decimal places.) m/s
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