Consider applying the Lagrange Multipliers method: Vf= (2x, 1), AVg = (2x, 2Ay). So 2x = 2x This is elementary algebra.

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answerhappygod
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Consider applying the Lagrange Multipliers method: Vf= (2x, 1), AVg = (2x, 2Ay). So 2x = 2x This is elementary algebra.

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Consider Applying The Lagrange Multipliers Method Vf 2x 1 Avg 2x 2ay So 2x 2x This Is Elementary Algebra 1
Consider Applying The Lagrange Multipliers Method Vf 2x 1 Avg 2x 2ay So 2x 2x This Is Elementary Algebra 1 (58.09 KiB) Viewed 47 times
Consider applying the Lagrange Multipliers method: Vf= (2x, 1), AVg = (2x, 2Ay). So 2x = 2x This is elementary algebra. One possible value for lambda is 1, then by algebra y 1/2. Now what are the values for x? the constrains is the unit circle. is the positive value for x is the negative value for x Type your answer as sqrt(a)/b
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