- Object Height Suppose An Object Is Thrown Straight Up From The Ground The Height After T Seconds Is Given By The Formu 1 (60.68 KiB) Viewed 49 times
Object Height. Suppose an object is thrown straight up from the ground. The height after t seconds is given by the formula h(t) = -4t3. + 76+² + 216 (a) The time in seconds when the object reached the highest point was Note: Round to 4 digits after the decimal point, if rounding is required 9.5 s 28.5 s 216 s Os 12.6667 s None of the other answers (b) The height is maximized at the critical point x = a because the second derivative test found f"(a) > O f"(a) < O f'(a) was negative to the left of x = a and positive to the right f'(a) was positive to the left of x = a and negative to the right f'(a) = 0 f"(a) = O