Iron(III) sulfide reacts with hydrobromic acid according to the reaction Fe₂S3(s) + 6HBr(aq) → 2FeBrç(s) + 3H₂S(g) A rea

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Iron(III) sulfide reacts with hydrobromic acid according to the reaction Fe₂S3(s) + 6HBr(aq) → 2FeBrç(s) + 3H₂S(g) A rea

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Iron Iii Sulfide Reacts With Hydrobromic Acid According To The Reaction Fe S3 S 6hbr Aq 2febrc S 3h S G A Rea 1
Iron Iii Sulfide Reacts With Hydrobromic Acid According To The Reaction Fe S3 S 6hbr Aq 2febrc S 3h S G A Rea 1 (50 KiB) Viewed 44 times
Iron(III) sulfide reacts with hydrobromic acid according to the reaction Fe₂S3(s) + 6HBr(aq) → 2FeBrç(s) + 3H₂S(g) A reaction mixture initially contains 1.28 mol Fe₂S3 and 19.5 mol HBr. Calculate the mass (g) of the excess reactant remaining after the reaction reaches completion. Enter your answer as an integer.
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