Chapter 6-Part 1: 1. What is the mass of a single atorn of iron? Molar mass Ir = 192.22 g/mol 192.22g mol 74.22-9 I mol

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Chapter 6-Part 1: 1. What is the mass of a single atorn of iron? Molar mass Ir = 192.22 g/mol 192.22g mol 74.22-9 I mol

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Chapter 6 Part 1 1 What Is The Mass Of A Single Atorn Of Iron Molar Mass Ir 192 22 G Mol 192 22g Mol 74 22 9 I Mol 1
Chapter 6 Part 1 1 What Is The Mass Of A Single Atorn Of Iron Molar Mass Ir 192 22 G Mol 192 22g Mol 74 22 9 I Mol 1 (360.41 KiB) Viewed 68 times
Chapter 6 Part 1 1 What Is The Mass Of A Single Atorn Of Iron Molar Mass Ir 192 22 G Mol 192 22g Mol 74 22 9 I Mol 2
Chapter 6 Part 1 1 What Is The Mass Of A Single Atorn Of Iron Molar Mass Ir 192 22 G Mol 192 22g Mol 74 22 9 I Mol 2 (240.08 KiB) Viewed 68 times
please help me find the mistakes! thank you in advance ☺️
Chapter 6-Part 1: 1. What is the mass of a single atorn of iron? Molar mass Ir = 192.22 g/mol 192.22g mol 74.22-9 I mol 6.022 x 10²3 atoms 10-4134 2. How many mol of Ca(BrO3)2 are there in 74.22 g of the compound? molar mass Ca: 40.08 3/mel -1 = 40.08 S Br: 79.90 g/mol · 1 = 79.90 9/mol 27.555* 3.192x10 E 0 1600 g/mol 3 = 45.000, 12.00 5 6.022 x 1023 mul C 24 167.48 9 9/mol 3. A compound was decomposed and determined to be 62.04 % C, 10.41% H and 27.55 %O by mass. What is the subscript for C in the empirical formula for this compound? 62.945 5.166 mm C 7.33 7x10 25 mol G4 G5
Chapter 6-Part 2: 1. What is the molarity of 71.3 g of NaCl dissolved in water to a total volume of 300.0 mlr 71.3 300.0 2. What mass of Caßr₂ (formula mass: 199.88 g/mol) is necessary to make 2.250 L of a 1.34 M solution? 3.0159 Cabr 3 =10.238 M 2.250 3. What volume (in L) of a 2.75 M glucose solution is necessary to make 4.35 L of a 0.125 M solution? EDTEL 11.763 25 CASMA 11.963 mel 95.7 L
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