Two charges of 91 9₁ = 1.7 μC and 92: d Need Help? P = -2.6 µC are d = 0.36 m apart at two vertices of an equilateral tr

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Two charges of 91 9₁ = 1.7 μC and 92: d Need Help? P = -2.6 µC are d = 0.36 m apart at two vertices of an equilateral tr

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Two charges of 91 9₁ = 1.7 μC and 92: d Need Help? P = -2.6 µC are d = 0.36 m apart at two vertices of an equilateral triangle as in the figure below. (a) What is the electric potential due to the 1.7-μC charge at the third vertex, point P? V 92 (b) What is the electric potential due to the -2.6-μC charge at P? V (c) Find the total electric potential at P. V (d) What is the work required to move a 3.4-μC charge from infinity to P? J Read It
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