Masses and diameter of the discs: (0.107 ± 0.005) kg M₂ (0.106 ± 0.005) kg D₁ D₂ (89.2 ± 0.8) mm = M₁ Table 1 - Angular

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answerhappygod
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Masses and diameter of the discs: (0.107 ± 0.005) kg M₂ (0.106 ± 0.005) kg D₁ D₂ (89.2 ± 0.8) mm = M₁ Table 1 - Angular

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Masses And Diameter Of The Discs 0 107 0 005 Kg M 0 106 0 005 Kg D D 89 2 0 8 Mm M Table 1 Angular 1
Masses And Diameter Of The Discs 0 107 0 005 Kg M 0 106 0 005 Kg D D 89 2 0 8 Mm M Table 1 Angular 1 (29.81 KiB) Viewed 25 times
Masses and diameter of the discs: (0.107 ± 0.005) kg M₂ (0.106 ± 0.005) kg D₁ D₂ (89.2 ± 0.8) mm = M₁
Table 1 - Angular accelerations of single and double discs pulled by various forces Single disc Double discs Falling mass (kg) ± 0.0005 kg 0.0053 0.0078 0.0105 0.0130 0.0158 0.0183 Angular accel. (rad/s²) ± 2% 10.53 15.64 21.03 25.77 30.62 35.37 Torque (N-m) ± 2% 0.00124 0.00179 0.00238 0.00291 0.00349 0.00399 Angular accel. (rad/s²) ± 2% 5.47 8.09 10.97 13.47 16.15 18.65 Torque (N-m) ± 2% 0.00125 0.00183 0.00244 0.00301 0.00363 0.00418
Question 1 (1 point) Using the mass and radius from the experimental details, calculate the moment of inertia (in g-m²) for the single disc (disc 1). Round your answer to 4 decimal places. NB. Be careful with the units! If you calculate the moment of inertia in kg.m² or kg.mm², you must convert to g.m². Saved
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