odule #3- Homework Begin Date: 9/20/2020 12:01:00 AM - Due Date: 6/12/2022 11:59:00 PM End Date: 9/28/2023 11:59:00 PM 3

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

odule #3- Homework Begin Date: 9/20/2020 12:01:00 AM - Due Date: 6/12/2022 11:59:00 PM End Date: 9/28/2023 11:59:00 PM 3

Post by answerhappygod »

Odule 3 Homework Begin Date 9 20 2020 12 01 00 Am Due Date 6 12 2022 11 59 00 Pm End Date 9 28 2023 11 59 00 Pm 3 1
Odule 3 Homework Begin Date 9 20 2020 12 01 00 Am Due Date 6 12 2022 11 59 00 Pm End Date 9 28 2023 11 59 00 Pm 3 1 (53.79 KiB) Viewed 18 times
odule #3- Homework Begin Date: 9/20/2020 12:01:00 AM - Due Date: 6/12/2022 11:59:00 PM End Date: 9/28/2023 11:59:00 PM 3%) Problem 26: Consider a spherical bacterium, with radius 1.4 µm, falling in water at 20° C. d d (in tuominati V= A Find the terminal speed of the spherical bacterium in meters per second, ignoring the buoyant force on the bacterium and assuming Stokes' lav viscous force. You will first need to note that the drag force is equal to the weight at terminal velocity. Take the density of the bacterium to be 1.45 x The viscosity of water at 20 °C is 1.002 x 103 kg/m's and the density is 998 kg/m³ 439. In Hints: 04 deduction per hint. Hints remaining: 1 cos() tan() * ( acos() E sin() cotan() asin() atan() acotan sinh() cosh() tanh() cotanh() Degrees O Radians Submit Hint 7 8 9 4 $ 6 1 2 3 0 NOCKFACE Fanshack I give up! Feedback: 0 deduction per feedback Grade Sum Deductions Potential Late Work S Late Potenti Submissions Attempts rem (0% per atten detailed view
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply