A proton (m 1.6726 x 1027 kg and q = 1.6 x 10-19 C) with speed 1.5 x 105m/s falls through a potential difference of -10

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answerhappygod
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A proton (m 1.6726 x 1027 kg and q = 1.6 x 10-19 C) with speed 1.5 x 105m/s falls through a potential difference of -10

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A Proton M 1 6726 X 1027 Kg And Q 1 6 X 10 19 C With Speed 1 5 X 105m S Falls Through A Potential Difference Of 10 1
A Proton M 1 6726 X 1027 Kg And Q 1 6 X 10 19 C With Speed 1 5 X 105m S Falls Through A Potential Difference Of 10 1 (21.15 KiB) Viewed 34 times
A proton (m 1.6726 x 1027 kg and q = 1.6 x 10-19 C) with speed 1.5 x 105m/s falls through a potential difference of -10 volts. What is the speed reached? 2.04 x 10 m/s 4.37 x 10 m/s 1.56 x 10³ m/s 2.04 x 10³ m/s 8.80 x 105 m/s
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