Answer Happy

use table 1 if you zoom in you could see the numbers. for some reason its blurry
Write a Mathlab program that can solve for the water flow rate distribution in a network of pipes using Hardy Cross Method capable of handling a maximum of ten loops with a maximum of ten lines in each loop. The program has to use Hazen Williams Equation for major pipe losses and symbols given on page 2.
1 3 1234 1 2 3 4 1234 TABLE 1 Loop Line Length Diameter Q() No. No. (in.) (efs) 3 1234 4.0 10.8 cfs 3.8 10560 15840 10560 16 15840 62496 A typical three-loop network. 12 14 16 6426 15840 16 13200 14 10560 12 10560 16 2022 2.4 cfs 15840 12 15840 10 1.M 15840 12 15840 12 Loop 1 42.3 cfs Loo 3.0 1.5 -4.0 3.8 1.7 0.3 -3.0 1.8 0.4 -1.0 -1.5 2.1 of 10.3 Loep 3 1 1.4 cs AEHAS BUDMA TABLE 2 Loop Node Line Swamer-Jain No No. 1 2 3 4 E44E 1234 1.4 cfs 1.4 cts Q (ef) 3.780 1.506 -1.640 14.040 2.980 0.880 -0.520 -3.780 1,753 0.353 <-1.047 -1.508 H (f) 120.000 102.902 84.085 90.816 120.000 select: 120.000 103.823 101.244 102.902 120.000 Cast Iron Pipe 102.902 77.730 74.734 84.085 102.902 60.00085 fr Y=1.082X16 $=8 2=10 S_1+1=3 QBA =-40 cfs Roc=+3.8 cts H--1.5 cfs