A long cylindrical electric heating element (p = 2700 kg/m³, cp = 900 J/kg-K, k = 240 W/m- K) with diameter, D = 12 mm,

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answerhappygod
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A long cylindrical electric heating element (p = 2700 kg/m³, cp = 900 J/kg-K, k = 240 W/m- K) with diameter, D = 12 mm,

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A Long Cylindrical Electric Heating Element P 2700 Kg M Cp 900 J Kg K K 240 W M K With Diameter D 12 Mm 1
A Long Cylindrical Electric Heating Element P 2700 Kg M Cp 900 J Kg K K 240 W M K With Diameter D 12 Mm 1 (29.95 KiB) Viewed 16 times
A long cylindrical electric heating element (p = 2700 kg/m³, cp = 900 J/kg-K, k = 240 W/m- K) with diameter, D = 12 mm, experiences a cross flow at 30°C and 8 m/s. The power consumption per unit length of element for heating is 1000 W/m. Determine a.) the steady- state surface temperature (°C) and b.) the time required (min) to reach within 10° of this temperature if the rod was initially at 30°C.
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