A 3-phase generator rated at phase voltage Va = 134/30⁰ kV with phase reactance Xa = j10 Ω per phase is connected to a 3

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A 3-phase generator rated at phase voltage Va = 134/30⁰ kV with phase reactance Xa = j10 Ω per phase is connected to a 3

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A 3-phase generator rated at phase voltageVa = 134/30⁰ kV with phase reactanceXa = j10 Ω per phase is connected to a 3-phasesupply with Vsupply = 130/0⁰ kV. Find theapparent power S of the generator. [Findphase current Ia fromVa = Vsupply +IaXa then calculate the apparentthree phase power S of the generator.Answer: S = 2,750/-26.5⁰ MVA total for 3phases.]
For example, a generator with such large apparent power would beused as the power supply of an electric arc furnace steel mill,connected directly to the trunk utility transmission lines. Utilitycustomers that use electric power at high voltages like this arecharged less per MWh and MW demand than other customers that usepower at lower voltages.
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