a. i. EN ii. $2 $1 SO 070 060 050 040 030 020 010 000 EN S3 S2 S1 SO Figure Q2 (a) F (x, y, z) = IIM (1,3,5,7) 015 014 0

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answerhappygod
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a. i. EN ii. $2 $1 SO 070 060 050 040 030 020 010 000 EN S3 S2 S1 SO Figure Q2 (a) F (x, y, z) = IIM (1,3,5,7) 015 014 0

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A I En Ii 2 1 So 070 060 050 040 030 020 010 000 En S3 S2 S1 So Figure Q2 A F X Y Z Iim 1 3 5 7 015 014 0 1
A I En Ii 2 1 So 070 060 050 040 030 020 010 000 En S3 S2 S1 So Figure Q2 A F X Y Z Iim 1 3 5 7 015 014 0 1 (61.09 KiB) Viewed 30 times
a. i. EN ii. $2 $1 SO 070 060 050 040 030 020 010 000 EN S3 S2 S1 SO Figure Q2 (a) F (x, y, z) = IIM (1,3,5,7) 015 014 013 012 011 010 8888888888 Figure Q2 (a) above shows 2 types of decoder that varies in term of its inputs. Generally, decoder is a digital circuit that performs the inverse operation of encoders. Besides that, it can also be used to implement an arbitrary function too. Choosing the right decoder above provided above, and by adding any basic gates if required, determine the implementation of the following output functions: 00 ▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬ Output P₁ and P₂ on a single decoder where P₁(a, b, c, d) = Em(1,3,5,7,13) P₂ (a, b, c, d) = Em(1,2,3,4,11,12,13,14) ·
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