IRA#6_5. The signal x(t) is sampled with a sampling frequency lower than the Nyquist rate to obtain x[n] = cos(213nr/500

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IRA#6_5. The signal x(t) is sampled with a sampling frequency lower than the Nyquist rate to obtain x[n] = cos(213nr/500

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Ira 6 5 The Signal X T Is Sampled With A Sampling Frequency Lower Than The Nyquist Rate To Obtain X N Cos 213nr 500 1
Ira 6 5 The Signal X T Is Sampled With A Sampling Frequency Lower Than The Nyquist Rate To Obtain X N Cos 213nr 500 1 (26.27 KiB) Viewed 37 times
IRA#6_5. The signal x(t) is sampled with a sampling frequency lower than the Nyquist rate to obtain x[n] = cos(213nr/500). If the sampling frequency is 1 kHz, then (a) the frequency of x(t) must be 213 Hz (b) the frequency of x(t) must be 500 Hz (c) the frequency of x(t) must be 1 kHz (d) the frequency of x(t) must be 2 kHz (e) none of the above Answer:
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