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A B FA,O= 10.0 mol/min CA10= 1,00 mol/L 2 KOH + H₂504 125 Kg + 541 APA = 01070 CA² mol / (L.S) V=1₁0 T=10051 CA=0/13 mol
Posted: Fri Jul 08, 2022 6:07 am
by answerhappygod
- A B Fa O 10 0 Mol Min Ca10 1 00 Mol L 2 Koh H 504 125 Kg 541 Apa 01070 Ca Mol L S V 1 0 T 10051 Ca 0 13 Mol 1 (156.57 KiB) Viewed 24 times
A B FA,O= 10.0 mol/min CA10= 1,00 mol/L 2 KOH + H₂504 125 Kg + 541 APA = 01070 CA² mol / (L.S) V=1₁0 T=10051 CA=0/13 mol/L CB=0188 mol/L - FA=1₁3 mol/min CA=013 MOLAL FB = 8.8 mol/min CB= 0,88 mol/L -K2SO4 + 2H₂0 → 170kg Production and Preparation of Potassium sulfate APProximately 1.5 million tons were Produced in 1985 a usually by reaction Potassium chloride with sulfuric acid in a Process similar to the Mannheim Process Mannheim for the Production of sodium sulfate. The Process meludes creating an intermediary. Potassium bisulfate an exothermic room temperatures Kel + H2504 Hel + KHSO 4 The second step of the Process is endothermic, and requires energy inputs Kel + KHSO 4 →→→ Hel + K2504 In the laboratory, it can be prepared through the reaction of either Potassium hydroxide or Potassium carbonate with sulfuric acid.