A B FA,O= 10.0 mol/min CA10= 1,00 mol/L 2 KOH + H₂504 125 Kg + 541 APA = 01070 CA² mol / (L.S) V=1₁0 T=10051 CA=0/13 mol

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

A B FA,O= 10.0 mol/min CA10= 1,00 mol/L 2 KOH + H₂504 125 Kg + 541 APA = 01070 CA² mol / (L.S) V=1₁0 T=10051 CA=0/13 mol

Post by answerhappygod »

A B Fa O 10 0 Mol Min Ca10 1 00 Mol L 2 Koh H 504 125 Kg 541 Apa 01070 Ca Mol L S V 1 0 T 10051 Ca 0 13 Mol 1
A B Fa O 10 0 Mol Min Ca10 1 00 Mol L 2 Koh H 504 125 Kg 541 Apa 01070 Ca Mol L S V 1 0 T 10051 Ca 0 13 Mol 1 (156.57 KiB) Viewed 22 times
A B FA,O= 10.0 mol/min CA10= 1,00 mol/L 2 KOH + H₂504 125 Kg + 541 APA = 01070 CA² mol / (L.S) V=1₁0 T=10051 CA=0/13 mol/L CB=0188 mol/L - FA=1₁3 mol/min CA=013 MOLAL FB = 8.8 mol/min CB= 0,88 mol/L -K2SO4 + 2H₂0 → 170kg Production and Preparation of Potassium sulfate APProximately 1.5 million tons were Produced in 1985 a usually by reaction Potassium chloride with sulfuric acid in a Process similar to the Mannheim Process Mannheim for the Production of sodium sulfate. The Process meludes creating an intermediary. Potassium bisulfate an exothermic room temperatures Kel + H2504 Hel + KHSO 4 The second step of the Process is endothermic, and requires energy inputs Kel + KHSO 4 →→→ Hel + K2504 In the laboratory, it can be prepared through the reaction of either Potassium hydroxide or Potassium carbonate with sulfuric acid.
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply