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A B FA,O= 10-0 mol/min CA10= 1100 mol/L PA≤ 01070 CA² mol/ (L.S) V=1₁0² T=1005/ CA=0/13 MOL/L, CB= 0188 mol/L FA=23mol/m
Posted: Fri Jul 08, 2022 6:07 am
by answerhappygod
- A B Fa O 10 0 Mol Min Ca10 1100 Mol L Pa 01070 Ca Mol L S V 1 0 T 1005 Ca 0 13 Mol L Cb 0188 Mol L Fa 23mol M 1 (154.24 KiB) Viewed 26 times
A B FA,O= 10-0 mol/min CA10= 1100 mol/L PA≤ 01070 CA² mol/ (L.S) V=1₁0² T=1005/ CA=0/13 MOL/L, CB= 0188 mol/L FA=23mol/min CA 13 MOLAL FB = 8.8 mol/min CB= 0,88 mol/L 2 KOH + H₂SO4 -> K2504 + 2H₂0 H2504 125 kg + 541 - 170kg Production and Preparation of Potassium sulfate APProximately 15 million tons were Produced in 1985 #a usually by reaction Potassium chloride with sulfuric acid in a Process similar to the Mannheim Process Mannheim for the Production of sodium sulfate. The Process includes creating an intermediary Potassium bisulfate an exothermic room temperatures Kel + H2SO4 - Hel + K H S 04 The second step of the Process is endothermic, and requires energy inputs Kel + KHSO 4 →→→→ Hel + K₂504 In the laboratory, it can be prepared through the reaction of either Potassium hydroxide or Potassium carbonate with sulfuric acid,