A B FA,O= 10-0 mol/min CA10= 1100 mol/L PA≤ 01070 CA² mol/ (L.S) V=1₁0² T=1005/ CA=0/13 MOL/L, CB= 0188 mol/L FA=23mol/m

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

A B FA,O= 10-0 mol/min CA10= 1100 mol/L PA≤ 01070 CA² mol/ (L.S) V=1₁0² T=1005/ CA=0/13 MOL/L, CB= 0188 mol/L FA=23mol/m

Post by answerhappygod »

A B Fa O 10 0 Mol Min Ca10 1100 Mol L Pa 01070 Ca Mol L S V 1 0 T 1005 Ca 0 13 Mol L Cb 0188 Mol L Fa 23mol M 1
A B Fa O 10 0 Mol Min Ca10 1100 Mol L Pa 01070 Ca Mol L S V 1 0 T 1005 Ca 0 13 Mol L Cb 0188 Mol L Fa 23mol M 1 (154.24 KiB) Viewed 25 times
A B FA,O= 10-0 mol/min CA10= 1100 mol/L PA≤ 01070 CA² mol/ (L.S) V=1₁0² T=1005/ CA=0/13 MOL/L, CB= 0188 mol/L FA=23mol/min CA 13 MOLAL FB = 8.8 mol/min CB= 0,88 mol/L 2 KOH + H₂SO4 -> K2504 + 2H₂0 H2504 125 kg + 541 - 170kg Production and Preparation of Potassium sulfate APProximately 15 million tons were Produced in 1985 #a usually by reaction Potassium chloride with sulfuric acid in a Process similar to the Mannheim Process Mannheim for the Production of sodium sulfate. The Process includes creating an intermediary Potassium bisulfate an exothermic room temperatures Kel + H2SO4 - Hel + K H S 04 The second step of the Process is endothermic, and requires energy inputs Kel + KHSO 4 →→→→ Hel + K₂504 In the laboratory, it can be prepared through the reaction of either Potassium hydroxide or Potassium carbonate with sulfuric acid,
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply