a) Figure Q2(a) illustrates a strip foundation of 2.0 m wide is placed at 1.0 m below the ground surface of a homogeneou

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A Figure Q2 A Illustrates A Strip Foundation Of 2 0 M Wide Is Placed At 1 0 M Below The Ground Surface Of A Homogeneou 1 (103.25 KiB) Viewed 52 times

a) Figure Q2(a) illustrates a strip foundation of 2.0 m wide is placed at 1.0 m below the ground surface of a homogeneous sand layer to support an allowable load 655 kN/m inclined at 80° with respect to the horizontal axis. The load will be acting at the base 0.2 m from the center line in the B direction. Determine the factor of safety against shear failure using Meyerhof's general equation of ultimate bearing capacity. Assume the ground water table is far below the ground surface and ignore sliding due to the horizontal load. Note: Meyerhof's bearing capacity factors No = 46.12, N₁ = 33.30, Ny = 48.03 1.0 m Shape factors Fcs = 1 + Depth factors Qall = 655 kN/m B Na LNC Inclination factors Contact pressure max amin Fcd= 1.133, Fad = 1.085, Fyd = 1 = Fai = Fai = (1-0) BL 0.8 m FIGURE Q2(a) 1+ 1 m B Fas = 1 += tang 6e B 2 (12 marks) y= 18 kN/m³ p=35° B Fys = 1-0.4- L 2 Fy₁ = (1-B) ²