Question 2 6 pts The actual combustion equation of octane in air was determined to be C8H18 + 1402 + 52.64N26CO2 + 2CO +

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

Question 2 6 pts The actual combustion equation of octane in air was determined to be C8H18 + 1402 + 52.64N26CO2 + 2CO +

Post by answerhappygod »

Question 2 6 Pts The Actual Combustion Equation Of Octane In Air Was Determined To Be C8h18 1402 52 64n26co2 2co 1
Question 2 6 Pts The Actual Combustion Equation Of Octane In Air Was Determined To Be C8h18 1402 52 64n26co2 2co 1 (66.15 KiB) Viewed 34 times
Question 2 6 pts The actual combustion equation of octane in air was determined to be C8H18 + 1402 + 52.64N26CO2 + 2CO + 9H₂O + 2.502 + 52.64N2 If 14.37 kg of carbon dioxide was produced, how much octane was burned? Express your answer in kg. Question 1 6 pts C4H10 is burned at an actual AFR of 16.5 kg fuel/kg air. What percent excess air or deficient air is this AFR? Express your answer in percent, positive if excess air or negative if deficient air. Question 3 6 pts The combustion of ethylene (C₂H4) in air gave the following balanced actual combustion reaction: C₂H4 +a (O2 + 3.76 N₂) 1.8 CO₂ + 0.2 CO + 2H₂O + (a - 2.9) O2 + 3.76a N₂ If the number of moles of O₂ supplied is a = 5.57, what is the absolute humidity of the products? Express your answer in kg v/kg dg. Question 4 5 pts A closed vessel contains moist air at 42°C and 1.36 bar. If the mole fraction of the water vapor in the air is 3.5%, what is the humidity ratio of the moist air? Express your answer in kg v/kg da.
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply