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Your answer is partially correct. The cylinder is displaced 0.19 m downward from its equilibrium position and is release

Posted: Fri Jul 08, 2022 5:48 am
by answerhappygod
Your Answer Is Partially Correct The Cylinder Is Displaced 0 19 M Downward From Its Equilibrium Position And Is Release 1
Your Answer Is Partially Correct The Cylinder Is Displaced 0 19 M Downward From Its Equilibrium Position And Is Release 1 (46.41 KiB) Viewed 45 times
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Your answer is partially correct. The cylinder is displaced 0.19 m downward from its equilibrium position and is released at time t = 0. Determine the displacement y and the velocity v when t = 3.7 s. The displacement and velocity are positive if downward, negative if upward. What is the magnitude of the maximum acceleration? Equilibrium position Answers: When t = 3.7 s: When t = 3.7 s: k = 131 N/m m 3.6 kg y = V = i 0.175 i -0.4352 The maximum acceleration: 9max= 6.913 m m/s m/s²