- Your Answer Is Partially Correct The Cylinder Is Displaced 0 19 M Downward From Its Equilibrium Position And Is Release 1 (46.41 KiB) Viewed 43 times
Please box answer
Please box answer
Please box answer
Please box answer
Your answer is partially correct. The cylinder is displaced 0.19 m downward from its equilibrium position and is released at time t = 0. Determine the displacement y and the velocity v when t = 3.7 s. The displacement and velocity are positive if downward, negative if upward. What is the magnitude of the maximum acceleration? Equilibrium position Answers: When t = 3.7 s: When t = 3.7 s: k = 131 N/m m 3.6 kg y = V = i 0.175 i -0.4352 The maximum acceleration: 9max= 6.913 m m/s m/s²