The block has a mass of 0.88 kg and moves within the smooth vertical slot. It starts from rest when the attached spring

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The block has a mass of 0.88 kg and moves within the smooth vertical slot. It starts from rest when the attached spring

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The Block Has A Mass Of 0 88 Kg And Moves Within The Smooth Vertical Slot It Starts From Rest When The Attached Spring 1
The Block Has A Mass Of 0 88 Kg And Moves Within The Smooth Vertical Slot It Starts From Rest When The Attached Spring 1 (33.84 KiB) Viewed 51 times
The Block Has A Mass Of 0 88 Kg And Moves Within The Smooth Vertical Slot It Starts From Rest When The Attached Spring 2
The Block Has A Mass Of 0 88 Kg And Moves Within The Smooth Vertical Slot It Starts From Rest When The Attached Spring 2 (59.78 KiB) Viewed 51 times
The block has a mass of 0.88 kg and moves within the smooth vertical slot. It starts from rest when the attached spring is in the unstretched position at A. s = 0.15 m. Neglect the size and mass of the pulley. Hint. The work of F can be determined by finding the difference Al in cord lengths AC and BC and using Up FAL. (Figure 1) Figure 0.4m HAM wwwww 03m- -100 N/m < 101 Part A Determine the magnitude of the constant vertical force F which must be applied to the cord so that the block amaina a speed 2.5 m/s when it reaches B Express your answer to three significant figures and include the appropriate units. F-105 μA 4 Provide Feedback → N Submit Previous Answers Request Answer Pearson CE X Incorrect; Try Again; 4 attempts remaining ? uration Inc. All rights reserved. Terms of Use | Privacy Policy | Permissions Contact Us | Next >>
3 SG н 0.3 K-IWNI 0.0 Fee 0.86 15 FAC LAC-05 LBC 2 0.4-155 = √0.25² +0.3² 2.0.391m 01 F (0.5 -0.391) - 1/4 (100) (-0,15) - (0.88.9.811 0.4) 2-1 (6.86) (2.5) 2 preto F (0.5-311)= 6:2 35 = 2.688 F (09) 6.235 - 2688 F2818 x (03)-31) - LOURD X X (0.5-391) +(100) (015)-(686-191-25571 (0.86782.5²
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