PART 2: One-Person See-Saw-Determine the mass of the meter stick 6. Remove all the clamps and masses from Part I. Move t

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answerhappygod
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PART 2: One-Person See-Saw-Determine the mass of the meter stick 6. Remove all the clamps and masses from Part I. Move t

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Part 2 One Person See Saw Determine The Mass Of The Meter Stick 6 Remove All The Clamps And Masses From Part I Move T 1
Part 2 One Person See Saw Determine The Mass Of The Meter Stick 6 Remove All The Clamps And Masses From Part I Move T 1 (99.95 KiB) Viewed 57 times
PART 2: One-Person See-Saw-Determine the mass of the meter stick 6. Remove all the clamps and masses from Part I. Move the fulcrum to 20 cm on the meter stick. 7. Place a clamp as close to the zero end as possible. Add mass incrementally to attain static equilibrium. 8. Calculate the ccw torque from the mass hanging at x=0. Assuming that the mass of the meter stick acts entirely at the x=50cm mark, what is the mass of the meter stick (if the beam is in equilibrium)? NOTE: This is a valid assumption--you can calculate torques due to the weight of an extended object by treating all the mass as if it is located at the center-of-mass. PART 3: Three forces and an unknown mass. 9. Remove all clamps and masses from Part II. Move the fulcrum to x=60cm. 10. Place a clamp at x=90cm and hang unknown mass #1 from the clamp. 11. Place a clamp at x=10cm and add enough mass to achieve equilibrium. 12. Calculate the forces and the clockwise and counterclockwise torques (remember to include the weight of the meter stick!). The total cw and ccw torques must be balanced in equilibrium, so what is mass #1?
Part II. clamp is at 220g added to 20 and 70 for clamp and hanger. total clamp is 290g to hit equilibrium with 290 @0cm I put the beam at 50 and added a weight hanger to 75cm or .25m from center. I added 500g with the addd 70g to equal 570g. I then reached equilibrium with the opposite side at 0cm and 290g. FLeft (N) .20 RLeft (m) T = CCW + F R Left Left (m.N) Rweight (m)
Determine the mass of the meterstick from the counterclockwise torque and the lever arm for the beam's weight (Rweight). I think the meter stick weighs roughly 200 grams. .5/.25 the one is side is 50cm from center and the other side is 25 cm from center. So 200g Part III. FLeft (N) Fweight (N) 8 RLeft (m) Rweight (N) T M1 (m.N) T τ Left = + F R (m.N) Weight Left Left = + F (m.N) + or -?? R Weight Weight Level arm for m₁ (RM₁) (m) Left side i have 120g @ 10cm for final clamp weight and the right side i have 250g @90cm for a final clamp weight, they are at equilbrium
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