091 r12 r₁ r₂ r12 [2.00cm î+ 4.00cm ĵ] - [4.00cm î+ 1.00cm ĵ] (2.00cm-4.00cm )i + (4.00cm - 1.00cm )Ĵ r12 = (-2.00cm )î+

[answerhappygod]

091 R12 R R R12 2 00cm I 4 00cm J 4 00cm I 1 00cm J 2 00cm 4 00cm I 4 00cm 1 00cm J R12 2 00cm I 1 (58.8 KiB) Viewed 50 times

091 r12 r₁ r₂ r12 [2.00cm î+ 4.00cm ĵ] - [4.00cm î+ 1.00cm ĵ] (2.00cm-4.00cm )i + (4.00cm - 1.00cm )Ĵ r12 = (-2.00cm )î+(3.00cm) j r12 The distance 12 is therefore 12 = √(-2 cm)²+(3 cm)² = We can now calculate the magnitude of the electric force between the two charges using Coulomb's Law. We will leave this up to you. Please show your work in the space bellow. (Check with your instructor before you move on.) 12 √√4+9cm = 3.61 cm. 92 When a variable (r12 for example) is bolded it represents a vector. When a variable (r12 for example) is not bold then ir represents a scalar. Now lets consider the direction of F21. This can be specified giving the angle of F21 relative to one of the coordinate axes or it can be specified by giving the components of F21. In this lab exercise we will concentrate on finding the components. On the diagram to the left, sketch F21 and its components. Also sketch the components of r12. What do you notice about the x and y components of each? The x and y components of each are proportional to each other.