The angular position of a rotating object is given by the equation 𝜃 = a + bt + ct2 where a, b, and c are constants. Her
Posted: Thu Jul 07, 2022 2:08 pm
The angular position of a rotating object is given by theequation
π = a + bt + ct2
where a, b,and c are constants.Here a = 1.60 rad, b = 2.06 rad/s, and c = 3.06 rad/s2.
(a) What is the position of the objectat t1 =0 and t2 = 3.90 s?π1 = radπ2 = rad(b) What is the angular speed of the objectat t1 =0 and t2 = 3.90 s?π1 = rad/sπ2 = rad/s(c) What is the angular acceleration of the objectat t1 =0 and t2 = 3.90 s?πΌ1 = rad/s2πΌ2 = rad/s2
π = a + bt + ct2
where a, b,and c are constants.Here a = 1.60 rad, b = 2.06 rad/s, and c = 3.06 rad/s2.
(a) What is the position of the objectat t1 =0 and t2 = 3.90 s?π1 = radπ2 = rad(b) What is the angular speed of the objectat t1 =0 and t2 = 3.90 s?π1 = rad/sπ2 = rad/s(c) What is the angular acceleration of the objectat t1 =0 and t2 = 3.90 s?πΌ1 = rad/s2πΌ2 = rad/s2