The angular position of a rotating object is given by the equation 𝜃 = a + bt + ct2 where a, b, and c are constants. Her

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answerhappygod
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The angular position of a rotating object is given by the equation 𝜃 = a + bt + ct2 where a, b, and c are constants. Her

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The angular position of a rotating object is given by theequation
๐œƒ = a + bt + ct2
where a, b,and c are constants.Here a = 1.60 rad, b = 2.06 rad/s, and c = 3.06 rad/s2.
(a) What is the position of the objectat t1 =0 and t2 = 3.90 s?๐œƒ1 = rad๐œƒ2 = rad(b) What is the angular speed of the objectat t1 =0 and t2 = 3.90 s?๐œ”1 = rad/s๐œ”2 = rad/s(c) What is the angular acceleration of the objectat t1 =0 and t2 = 3.90 s?๐›ผ1 = rad/s2๐›ผ2 = rad/s2
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