A single slit of width d= 0.08 mm is illuminated by light of two wavelengths, λ = 461 nm and 2 = 658 nm. The diffraction

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answerhappygod
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A single slit of width d= 0.08 mm is illuminated by light of two wavelengths, λ = 461 nm and 2 = 658 nm. The diffraction

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A single slit of width d= 0.08 mm is illuminated by light of two wavelengths, λ = 461 nm and 2 = 658 nm. The diffraction pattern appears on a screen 1.07 m away. rad (a) Calculate the angles at which the third dark fringe appears for each wavelength. 0461 = rad 0658= m Enter m Help Enter Single Slit Diffraction (b) Calculate the width of the central bright fringe for each wavelength. d461 = d658= Ө Enter Help Enter
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