A proton in a synchrotron is moving in a circle of radius 1 km and increasing its speed by v(t) where C₁ 8.6 × 105 m/s a
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A proton in a synchrotron is moving in a circle of radius 1 km and increasing its speed by v(t) where C₁ 8.6 × 105 m/s a
Question a. What is the proton's total acceleration at t 9.9225 a = x 10⁹ m/s² b. At what time does the expression for the velocity become unphysical? t = 54.71 ✔ S = : 5.0 s? Hint 1 Hint 2 = C₁ + c₂t²
A proton in a synchrotron is moving in a circle of radius 1 km and increasing its speed by v(t) where C₁ 8.6 × 105 m/s and C2 - 105 m/s³. 2 = - Submit