(5%) Problem 14: An arrow is shot from a height of 1.5 m toward a cliff of height H. It is shot with a velocity of 29 m/

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

(5%) Problem 14: An arrow is shot from a height of 1.5 m toward a cliff of height H. It is shot with a velocity of 29 m/

Post by answerhappygod »

5 Problem 14 An Arrow Is Shot From A Height Of 1 5 M Toward A Cliff Of Height H It Is Shot With A Velocity Of 29 M 1
5 Problem 14 An Arrow Is Shot From A Height Of 1 5 M Toward A Cliff Of Height H It Is Shot With A Velocity Of 29 M 1 (12.39 KiB) Viewed 52 times
5 Problem 14 An Arrow Is Shot From A Height Of 1 5 M Toward A Cliff Of Height H It Is Shot With A Velocity Of 29 M 2
5 Problem 14 An Arrow Is Shot From A Height Of 1 5 M Toward A Cliff Of Height H It Is Shot With A Velocity Of 29 M 2 (36.93 KiB) Viewed 52 times
(5%) Problem 14: An arrow is shot from a height of 1.5 m toward a cliff of height H. It is shot with a velocity of 29 m/s at an angle of 60° above the horizontal. It lands on the top edge of the cliff 3.59 s later.
A 33% Part (a) What is the height H of the cliff in m? H = sin() cotan() atan() cosh() cos() asin() tan() acos() E sinh() cotanh() acotan() tanh() Degrees Radians Submit Hint ( 7 8 4 5 1 2 42 0 VO BACKSPACE 9 HOME 6 3 FND CLEAR Frrobesk Igave upy Feedback: 2% deduction per feedback. Hints: 2% deduction per hint. Hints remaining: A 33% Part (b) What is the maximum height reached by the arrow along its trajectory in meters? A 33% Part (c) What is the arrow's speed just before hitting the cliff in m/s?
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply