A 0 209 Kg Particle Undergoes Simple Harmonic Motion Along The Horizontal X Axis Between The Points X 0 331 M And X 1 (26.44 KiB) Viewed 47 times
A 0 209 Kg Particle Undergoes Simple Harmonic Motion Along The Horizontal X Axis Between The Points X 0 331 M And X 2 (23.84 KiB) Viewed 47 times
A 0.209-kg particle undergoes simple harmonic motion along the horizontal x-axis between the points x₁ = -0.331 m and x₂ = 0.393 m. The period of oscillation is 0.581 s. Find the frequency, f, the equilibrium position, xeq, the amplitude, A, the maximum speed, Umax, the maximum magnitude of acceleration, amax, the force constant, k, and the total mechanical energy, Erot f= A = khen Et= Hz m m/s² J Xeq= Umax k= m m/s N/m
The spaceship Intergalactica lands on the surface of the uninhabited Pink Planet, which orbits a rather average star in the distant Garbanzo Galaxy. A scouting party sets out to explore. The party's leader-a physicist, naturally-immediately makes a determination of the acceleration due to gravity on the Pink Planet's surface by means of a simple pendulum of length 1.44 m. She sets the pendulum swinging, and her collaborators carefully count 105 complete cycles of oscillation during 207 s. What is the result? acceleration due to gravity: m/s²
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