A Disk Of Radius 29 0 Cm Is Free To Turn About An Axde Perpendicular To It Through Its Center It Has Very Thin But Stro 1 (36.9 KiB) Viewed 47 times
A Disk Of Radius 29 0 Cm Is Free To Turn About An Axde Perpendicular To It Through Its Center It Has Very Thin But Stro 2 (56.24 KiB) Viewed 47 times
A disk of radius 29.0 cm is free to turn about an axde perpendicular to it through its center. It has very thin but strong string wrapped around its rim, and the string is attached to a ball that is pulled tangentially away from the rim of the disk (Eigure 1). The pull increases in magnitude and produces an acceleration of the ball that obeys the equation a (t)= At, where it is in seconds and A is a constant. The cylinder starts from rest, and at the end of the third second, the ball's acceleration is 2.30 m/s² Figure Disk Ball 1 of 1 Pull Express your answer in meters per second cubed. A-15 Submit VE ΑΣΦ 1 Part B X Incorrect; Try Again; 29 attempts remaining Previous Answers Request Answer a(t) - ? Express the angular acceleration of the disk as a function of time Express your answer in radians per second cubed multiplied by t VAE 4 Constants
▼ How much time after the disk has begun to turn does it reach an angular speed of 15.0 rad/s? Express your answer in seconds. t = 15. ΑΣΦ Submit Part D Request Answer 0-00 = ? Through what angle has the disk turned just as it reaches 15.0 rad/s? (Hint: See Section 2.6 in the textbook.) Express your answer in radians. ΓΧΕΙ ΑΣΦ S ? rad
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