The Magnitude Of The Magnetic Field At The Center Of A 37 Turn Loop Of Wire Is 1 9 X 10 6 T Calculate The Current In Th 1 (38.71 KiB) Viewed 42 times
The Magnitude Of The Magnetic Field At The Center Of A 37 Turn Loop Of Wire Is 1 9 X 10 6 T Calculate The Current In Th 2 (58.04 KiB) Viewed 42 times
The magnitude of the magnetic field at the center of a 37-turn loop of wire is 1.9 x 10-6 T. Calculate the current in the loop if the radius is 17 cm. (Give your answer in amps but don't include the units.)
c = 3 x 108 m/s €0 = 8.85 x 10-¹2 Chapter 21 magnetic force on moving charge: |F| = |g||||B|| magnetic force on straight current: |F|= IL|B| magnetic field produced by long current: |B|- E=cB &=-N- U= magnetic field produced by loop current: Boenter = NHOT 2R Chapter 22 EmotionalUBL ΔΦ At E² N.m² Erms Chapter 201 Emar √2 -B² 140 H40 47 x 10-7 = BA cos 0 S 11 Brms P A нов 2пт Bmar √2 <=Cu T-m A
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