Different cells use different enzymes to metabolize glucose, C6H₁2O6(aq), in the absence of oxygen. Muscle cells will co

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Different Cells Use Different Enzymes To Metabolize Glucose C6h 2o6 Aq In The Absence Of Oxygen Muscle Cells Will Co 1 (33.68 KiB) Viewed 48 times

Different Cells Use Different Enzymes To Metabolize Glucose C6h 2o6 Aq In The Absence Of Oxygen Muscle Cells Will Co 2 (28.6 KiB) Viewed 48 times

Different Cells Use Different Enzymes To Metabolize Glucose C6h 2o6 Aq In The Absence Of Oxygen Muscle Cells Will Co 3 (29.78 KiB) Viewed 48 times

Different cells use different enzymes to metabolize glucose, C6H₁2O6(aq), in the absence of oxygen. Muscle cells will convert glucose to lactic acid, C,H,O,(aq), as represented by the following equation. C6H₁2O6(aq) muscle cell enzymes, 2C,H,O3(aq) + 125.7 kJ Yeast cells will convert glucose to ethanol, C₂H₂OH(aq), and carbon dioxide, CO₂(g), as represented by the following equation. C6H12O6(aq) yeast cell enzymes, 2C₂H₂OH(aq) + 2 CO₂(g) + 79.9 kJ A student dissolved 6.50 g of glucose into each of two identical polystyrene calorimeters containing 100.0 mL of water. She then added muscle cell enzymes to the contents of one calorimeter and yeast cell enzymes to the contents of the other, covered the calorimeters, and monitored the temperature change in each.
Use the following additional information to answer the last question The student collected the following data during the experiment. 6.50 g 0.10 g 100.0 mL Mass of glucose Mass of muscle cell enzymes Volume of water in the calorimeter Initial temperature of calorimeter water Final temperature of calorimeter water Assume the specific heat capacity of the solution is the same as that of water. 21.4 °C 31.5 °C 4. What is the experimental value for the molar enthalpy of reaction for glucose in this experiment? [3 marks]
A student mixed 150.0 mL of 1.50 mol/L sodium hydroxide solution with 80.0 mL of 1.50 mol/L solution of sulfuric acid, both at an initial temperature of 21.0°C. If the molar enthalpy of neutralization for sodium hydroxide is -53.5 kJ/mol, what is the final temperature of the solution? [3 marks] NACH, OH = mest 0.23 kg nem 1.0.150 1.50ml = 0.225mal 6.225 63. SKI Fee 460.225 0.23 kg = 53.5 4.19 E 6p - 61 t = 12.490...c +21.0℃ = 33.4%... c te = 33.5 c 4.19KJ Make not = 12.490... "C Draw a potential energy diagram for the above reaction [3 marks] 2N₂01 + 11₂.504 (0) 2HOH() + Na ₂504 (