- 26 The Combustion Of 2 Propanol M 60 0 G Mol Occurs According To The Reaction 2 Ch3chohch3 L Ah Kj Mol 9 O G 1 (36.78 KiB) Viewed 51 times
26. The combustion of 2-propanol (M= 60.0 g/mol) occurs according to the reaction: 2 CH3CHOHCH3(l) AH,(kJ/mol) +9 O₂(g)
-
answerhappygod
- Site Admin
- Posts: 899603
- Joined: Mon Aug 02, 2021 8:13 am
26. The combustion of 2-propanol (M= 60.0 g/mol) occurs according to the reaction: 2 CH3CHOHCH3(l) AH,(kJ/mol) +9 O₂(g)
26. The combustion of 2-propanol (M= 60.0 g/mol) occurs according to the reaction: 2 CH3CHOHCH3(l) AH,(kJ/mol) +9 O₂(g) →6 CO₂(g) +8 H₂O(l) CH3CHOHCH3(C) -318.2 CO₂(g) H₂O(l) -393.5 -285.8 What is q for the combustion of 15.0 g of 2-propanol? (A)-5.01 x 10² kJ (B)-1.00 x 10³ kJ (C) 2.01 x 10³ kJ (D)-4.01 x 10³ kJ